waremark wrote:Fenland Flyer posted an explanation last year - if I understand him correctly it would give 87% for 20 1's and 7 2's, 89% would suggest only 6 2's. ...
This is what FF said: ...
Can you explain how you arrive at 87%, since it is close to the true figure.
I came to 79.4% using FF's workings, as you reported in page 2 of this thread and again here.
Basically, my working was as follows;
7 2's = 14, 20 1's = 20, sum = 34
As FF said, divide total "into" number of categories marked, 27/34 = 79.4%. Not sure what he meant by "into", but obviously we don't want a score above 100%, and the above method is consistent with the examples he posted for all 1's, all 2's etc.
The only other way I can think of would be a simple % of the total possible mark, for which we need to convert the scores so the 1's become 5's, 2's become 4's, etc
Then, the max score from 27 categories would be 27x5 (135)
Our SA candidate scored 20x5 plus 7x4 (128), equals 94.8% of the max mark, which is how I think some of the other guessers on here have arrived at that figure.
This is puzzling me.